5x^2+39x-110=0

Solution for 5x^2+39x-110=0 equation:

5x^2+39x-110=0

a = 5; b = 39; c = -110;
Δ = b2-4ac
Δ = 392-4·5·(-110)
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3721}=61$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-61}{2*5}=\frac{-100}{10}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+61}{2*5}=\frac{22}{10}
=2+1/5
$